分组循环

# 2765. 最长交替子序列 (opens new window)

见灵*直播讲解；

# 228. 汇总区间 (opens new window)

class Solution {
    public List<String> summaryRanges(int[] nums) {
        List<String> res = new ArrayList<>();
        int start = 0;
        for(int i=0;i<nums.length;i++){
            if(i+1==nums.length || nums[i+1]!=nums[i]+1){
                if(start==i)
                    res.add(String.valueOf(nums[start]));
                else
                    res.add(String.format("%d->%d",nums[start],nums[i]));
                start = i+1;
            }
        }
        return res;
    }
}

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# 1446. 连续字符 (opens new window)

class Solution {
    public int maxPower(String s) {
        int n=s.length();
        int i=1,ans=1;
        while(i<n){
            if(s.charAt(i)!=s.charAt(i-1)){
                i++;
                continue;
            }
            int start = i;
            i++;
            while(i<n && s.charAt(i)==s.charAt(i-1)){
                i++;
            }
            ans = Math.max(ans,i-start+1);
        }
        return ans;
    }
}

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